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5y^2-2=47
We move all terms to the left:
5y^2-2-(47)=0
We add all the numbers together, and all the variables
5y^2-49=0
a = 5; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·5·(-49)
Δ = 980
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{980}=\sqrt{196*5}=\sqrt{196}*\sqrt{5}=14\sqrt{5}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{5}}{2*5}=\frac{0-14\sqrt{5}}{10} =-\frac{14\sqrt{5}}{10} =-\frac{7\sqrt{5}}{5} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{5}}{2*5}=\frac{0+14\sqrt{5}}{10} =\frac{14\sqrt{5}}{10} =\frac{7\sqrt{5}}{5} $
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